Page 1 of 2

Random Picture Thread

PostPosted: Fri Jun 05, 2009 8:51 pm
by GUARD!AN
If you can't see it I guess right click and view image.

One of my favorites, this one is for Turkey:

Image

Re: Random Picture Thread

PostPosted: Fri Jun 05, 2009 9:13 pm
by tens0r
Image
Jawa never gets old.

Re: Random Picture Thread

PostPosted: Fri Jun 05, 2009 10:30 pm
by Turky
GUARD!AN wrote:If you can't see it I guess right click and view image.

One of my favorites, this one is for Turkey:

Image


ROFL, you had me hooked before I saw "This one is for Turkey"

edit: ok got the first 1 (lmfao)


first stage: raptor speeding up

v=v0 + at , where:

v0 = initial velocity (which is 0 in this case)
v = final velocity (25 m/s)
a = acceleration (4.0 m/s^2)
t = time in seconds

solving for t, we get t = 6.25 seconds. So the raptor spends 6.25s speeding up.

During that time, we must find how far it went. To do this, we rewrite v as dx/dt, and integrate to get x = 2t^2. So x(t) = 2t^2 for the raptor whle it is speeding up.

Since it spends 6.25s speeding up, it follows by plugging into x(t) that the raptor travels 78.125m in this time.

In this same time, you have a 40m head start and, for all intents and purposes, can be presumed to (almost) instantly hit a max speed of 6m/s. Since they give no details about how long it takes, only that it doesn't take long, we'll presume that you instantly speed off at 6m/s.

So then, x(t) = vt = 6t for you. So in 6.25 seconds, you will travel 37.5m. Add on your head start, and you'll be 77.5m from the raptor's starting point--just short of the same distance that the raptor travels in this time. Ther

Since it is apparent that the raptor will not quite get to its peak velocity before overtaking you, we will do some optional fine-tuning which will tell us how fast the raptor was going when it caught up to you. To do this, we yews the equation v^2 = v0^2 + 2ax, where v is the final velocity (what we're looking for), v0 is the initial velocity (which is zero), x is the distance traversed (77.5m), and a is the acceleration (4m/s^2). By simple algebra, we obtain v = 24.9 m/s. Which is reasonable, since the raptor was just about to reach the distance at which he would reach peak velocity.

Re: Random Picture Thread

PostPosted: Sat Jun 06, 2009 4:26 pm
by Darth_Wayne
Image

Re: Random Picture Thread

PostPosted: Sat Jun 06, 2009 4:54 pm
by Duo
I already made a random picture thread you scrote.

Re: Random Picture Thread

PostPosted: Sun Jun 07, 2009 2:17 am
by GUARD!AN
Image

Re: Random Picture Thread

PostPosted: Sun Jun 07, 2009 11:56 am
by Turky
GUARD!AN wrote:Image


ROOOOFL.

suz guard's thread > duo's. plz delete duo's or move his posts here thx.

Re: Random Picture Thread

PostPosted: Sun Jun 07, 2009 12:28 pm
by Helaku
Turky wrote:
GUARD!AN wrote:If you can't see it I guess right click and view image.

One of my favorites, this one is for Turkey:

Image


ROFL, you had me hooked before I saw "This one is for Turkey"

edit: ok got the first 1 (lmfao)


first stage: raptor speeding up

v=v0 + at , where:

v0 = initial velocity (which is 0 in this case)
v = final velocity (25 m/s)
a = acceleration (4.0 m/s^2)
t = time in seconds

solving for t, we get t = 6.25 seconds. So the raptor spends 6.25s speeding up.

During that time, we must find how far it went. To do this, we rewrite v as dx/dt, and integrate to get x = 2t^2. So x(t) = 2t^2 for the raptor whle it is speeding up.

Since it spends 6.25s speeding up, it follows by plugging into x(t) that the raptor travels 78.125m in this time.

In this same time, you have a 40m head start and, for all intents and purposes, can be presumed to (almost) instantly hit a max speed of 6m/s. Since they give no details about how long it takes, only that it doesn't take long, we'll presume that you instantly speed off at 6m/s.

So then, x(t) = vt = 6t for you. So in 6.25 seconds, you will travel 37.5m. Add on your head start, and you'll be 77.5m from the raptor's starting point--just short of the same distance that the raptor travels in this time. Ther

Since it is apparent that the raptor will not quite get to its peak velocity before overtaking you, we will do some optional fine-tuning which will tell us how fast the raptor was going when it caught up to you. To do this, we yews the equation v^2 = v0^2 + 2ax, where v is the final velocity (what we're looking for), v0 is the initial velocity (which is zero), x is the distance traversed (77.5m), and a is the acceleration (4m/s^2). By simple algebra, we obtain v = 24.9 m/s. Which is reasonable, since the raptor was just about to reach the distance at which he would reach peak velocity.


Upon reading the first uncommon english converstation word(its bolded) I stranded....really,i Lost track of what you posted :D

Re: Random Picture Thread

PostPosted: Mon Jun 08, 2009 10:55 pm
by GUARD!AN
Image

Re: Random Picture Thread

PostPosted: Mon Jul 20, 2009 12:29 am
by Darth_Wayne
tens0r wrote:Image
Jawa never gets old.


LOL OMG!!!!!!